Given that f (x) = (m-1) x2 + MX + 1 is an even function, then the sum of the maximum and minimum of F (x) in the interval [- 2,1] is equal to______ ．

∵ f (x) = (m-1) x2 + MX + 1 is an even function, ∵ M = 0, ∵ f (x) = - x2 + 1, then the maximum and minimum values of F (x) in the interval [- 2,1] are - 3 and 1 respectively, then the sum of the maximum and minimum values of F (x) in the interval [- 2,1] is equal to - 2, so the answer is: - 2

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