After the resistor R1 and R2 are connected in series to a 3V power supply, it is known that the resistor R1 = 3 Ω and the consumed power P1 = 0.12W Find the current on the circuit, the voltage at both ends of resistance R1, and the power of R2

I^2*R1=P1
I=(P1/R1)^1/2=0.2A
U1=I*R1=0.2*3=0.6V
P2=UI-P1=3*0.2-0.12=0.48W

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