The derivative of log3cos ^ 2x? The answer is with log3e. How to calculate it?

If f (x) is also a composite function, then enter the inner layer, this is the chain derivation rule of the composite function, specifically: [log3 (COS ^ 2 x)] '= 1 / (COS ^ 2 x) Ln3 * (COS ^ 2 x)] = 1 / (C

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