Known function FX = x ^ 2-4x + 6, x > = 0, FX = 2x + 4, X

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• 1. Function FX = 1 / 4 ^ x + m (M > 0), when X1 + x2 = 1, FX1 + FX2 = 1 / 2, 1, find the value of M 2. The known sequence an satisfies an = F0 + F (1 / N) + F (2 / N) + +F (n-1 / N), find an 3, if Sn = a1 + A2 + a3 + +An, Sn 4 ^ x + m is the denominator x1, and X2 belongs to R
• 2. FX is an odd function defined on R, XF '(x) + F (x) on (- infinity, O)
• 3. If f (x) is an odd function defined on R and is an increasing function in (0, + ∞), and f (2) = 0, then the solution set of the inequality XF (x) < 0 is______ ．
• 4. It is known that the function f (x) is a monotone increasing function defined on (0, ∞), and f (XY) = f (x) + F (y) for any X and Y in the domain of definition f（3）=1. (1) Finding the value of F (1) (2) Solving inequality f (3x) + F (2x-1) ≤ 2
• 5. (a+b)²－9(ac+bc)+20c² (a²+5a)²+8(a²+5a)+16
• 6. m^5－m^4＋m^3－2m^2＋2m－2
• 7. Extracting common factor and decomposing factor (x+2y)²+x+2y The polynomial A & # 178; (x-a) + a (A-X) is factorized, and the result is () A、（x-a）（a²+a） B、a（x-a）（a+1） C、a（x-a）（a-1） D、a（x+a）（a-1） 2013 times of (- 8) + 2012 times of (- 8) can be divided by () A、3 B、5 C、7 D、9 Can 23 times of 5 - 21 times of 5 be divided by 120? （a-3）²-（2a-6）
• 8. Factorization: - 4 (x-2y) 2 + 9 (x + y) 2
• 9. Do a few questions, factoring and so on X3-9x = 16x fourth power - 1 = 2x2 + 4x + 2 = 2A - (a + b) (a-b)= 3a2b(2a－3b2)= (-1＋2a)2= (a+b)2-(a-b)2= （x-2y+4）(x-2y-4)= -a2+81= ay2-2a2y+3= 9y3-2y= Calculate the value of (2-A) (a + 2) + (- b-2) (2-B), where a = √ 2, B = 2 √ 2
• 10. Several factorization problems 1. (1) factorization n ^ 3-N (2) if n is an integer, try to explain that n ^ 3-N is a multiple of 6 (1) (19.99 + 4.99) 2-4 * 19.99 * 4.99 Urgent need before 17:00 p.m. on December 26, thank you
• 11. The definition of function monotonicity is as follows: if X1 is less than x2 and FX1 is less than or equal to FX2, then the function is monotone increasing function. Why is there equal to in the definition
• 12. For the function f (x) defined on the interval D, if ∀ x1, X2 ∈ D, and X1 & lt; X2, there is & nbsp; If f (x 1) ≥ f (x 2), then f (x) is a "non increasing function" on interval D. if f (x) is a "non increasing function" on interval [0,1] and f (0) = L, f (x) + F (l-x) = L, then f (x) ≤ - 2x + 1 holds when x ∈ [0,14]. There are the following propositions: ① ∀ x ∈ [0,1], f (x) ≥ 0; ② when x1, X2 ∈ [0,1] and x1 ≠ X2, f (x 1) ≠ f (x) ③ f (18) ）+F (511) + F (713) + F (78) = 2; 4. When x ∈ [0,14], f (f (x)) ≤ f (x). Where the serial numbers of all propositions that you think are correct are______ ．
• 13. If the function FX defined on R satisfies f (x + y) = f (x) + F (y) + 2XY [XY belongs to R] f (1) = 2, then f (- 2) =? Please be more detailed! 20 points will be sent! If it's OK, points will be added! The earlier you answer, the more points will be added. Thank you
• 14. When x > 0, the function FX is meaningful and satisfies F 2 = 1, f (XY) = FX + FY, FX is an increasing function (1) Verification: F (1) = 0 (2) If f (3) + F (4-8x) > 2, find the value range of X
• 15. Given that f (x) is an odd function in the domain of definition on the interval [1, - 1] and is an increasing function, the value of F (0) can be obtained,
• 16. It is known that the function f (x) is an odd function in the domain of definition (&; - 2,2) It is known that the function f (x) is an odd function in the domain of definition (&; - 2,2) and increases monotonically in the interval [0,2]. The solution to the inequality f (x-1) + F (x ^ 2-1) < 0 The answer is (- 1,1), why
• 17. It is known that the function f (x) is an odd function in the domain (- 2,2). The odd function in the interval [0,2] decreases monotonically in the interval [0,2] Solve the inequality f (x-1) + F (x ^ 2-1) < 0
• 18. It is known that the function f (x) is an odd function whose domain of definition is R. when x > 0, f (x) = x-x + 1, then if x
• 19. For an odd function defined on R, when x > 0, f (x) = x ^ 2-2x + 1
• 20. Let f (x) be an odd function defined on R