If the function FX defined on R satisfies f (x + y) = f (x) + F (y) + 2XY [XY belongs to R] f (1) = 2, then f (- 2) =? Please be more detailed! 20 points will be sent! If it's OK, points will be added! The earlier you answer, the more points will be added. Thank you

If the function FX defined on R satisfies f (x + y) = f (x) + F (y) + 2XY [XY belongs to R] f (1) = 2, then f (- 2) =? Please be more detailed! 20 points will be sent! If it's OK, points will be added! The earlier you answer, the more points will be added. Thank you

Let x = - 2 y = 1 f (- 2 + 1) = f (- 2) + F (1) - 4 so f (- 1) = f (- 2) - 2 let x = - 1 y = 1 f (- 1 + 1) = f (- 1) + f (1) - 2 so f (0) = f (- 1) let x = 0 y = 1 f (0 + 1) = f (0) + F (1) so f (0) = 0 in conclusion, f (- 2) = f (- 1) + 2 = f (0) + 2 = 2