It is known that F X is an odd function defined on R and satisfies f (x 4) = f (x). When x ∈ (0,2), f (x) = 2x & sup2;, then f (7)=
Because f (x + 4) = f (x),
So f (7) = f (4 + 3) = f (3) = f (- 1 + 3) = f (- 1)
And f (x) is an odd function
So let f (7) = f (- 1) = - f (1) = - (2 x 1 & sup2;) = - 2
Hope to help you
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