6. Given that the function f (n) defined on a positive integer satisfies the following condition (1) f (M + n) = f (m) + F (n) + Mn (2) f (3) = 6, then f (2000) =?

6. Given that the function f (n) defined on a positive integer satisfies the following condition (1) f (M + n) = f (m) + F (n) + Mn (2) f (3) = 6, then f (2000) =?

From the condition, f (2) = 2F (1) + 1F (3) = f (1) + F (2) + 2 = 3f (1) + 3, so f (1) = 1 let m = 1, f (n + 1) = f (n) + F (1) + n = f (n) + N + 1 is a sequence problem, f (n) = f (n-1) + n = f (n-2) + N + (n-1) =... = f (1) + N + (n-1) +... + 2 =