If a = {X / x = a + B = ab-3, a, B ∈ (0, + ∞)} complete set u = R, then CUA=

If a = {X / x = a + B = ab-3, a, B ∈ (0, + ∞)} complete set u = R, then CUA=

a+b=ab-3
Because a ^ 2 + B ^ 2 + 2Ab ≥ 2Ab + 2Ab = 4AB, that is ab ≤ (a + b) ^ 2 / 4
So a + B ≤ (a + b) ^ 2 / 4-3
Let a + B = t
t≤t^2/4-3
t^2-4t-12≥0
t≤-2 or t≥6
Obviously, a + b > 0
So x = a + B ≥ 6
The complement of a is a = {x | X

Elden Ring Premiere

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