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a+b=ab-3 因為a^2+b^2+2ab≥2ab+2ab=4ab即ab≤(a+b)^2/4 所以a+b≤(a+b)^2/4-3 令a+b=t t≤t^2/4-3 t^2-4t-12≥0 t≤-2 or t≥6 顯然a+b>0 所以x=a+b≥6 A的補集是A={x| x
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