Use the substitution method to solve the following equations, do not give the answer directly （1） 3x + 4y = 16 ① 5x - 6y = 33 ② （2）4（x-y-1）= 3（1-y）- 2 ① x/2 + y/3 =2 ②

Use the substitution method to solve the following equations, do not give the answer directly （1） 3x + 4y = 16 ① 5x - 6y = 33 ② （2）4（x-y-1）= 3（1-y）- 2 ① x/2 + y/3 =2 ②

one
3x + 4Y = 16, multiply both sides by 3 to get 9x + 12Y = 48, and then move the term 12Y = 48-9x
5x-6y = 33, both sides multiplied by 2, is 10x-12y = 66
12Y into the second equation
10x-48+9x=66
19x=114
x=6
y=-1/2
two
4 (x-y-1) = 3 (1-y) - 2, y = 4x-5 after simplification
X / 2 + Y / 3 = 2 multiply both sides by 6 3x + 2Y = 12
Taking y into 3x + 2Y = 12
3x+8x-10=12
11x=22
x=2
y=3