Thank you

It's very simple
∵PD‖AB,PE‖AC
∴∠ABP=∠DPB,∠ACP=∠EPC
∵ BP and CP divide ∠ ABC and ∠ ACB equally
∴∠ABP=∠DBP,∠ACP=∠PCB
∴∠DPB=∠DBP,∠EPC=∠PCB
∴BD=PD,PE=EC
∴C△PDE=PD+PE+DE=BD+DE+EC=BC=5cm

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