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Through the point B (2,1), make a straight line L intersection hyperbola x square - y square / 2 = 1 at two points a and B, and M is the midpoint of AB, find the equation of straight line L
If the slope of L doesn't exist, then it's perpendicular to the X axis, so it's x = 2. At this time, the intersection of L and hyperbola is symmetric about the X axis, so the midpoint is on the X axis. If the slope exists, then Y-1 = K (X-2) y = KX + (1-2k) is substituted into 2x & sup2; - Y & sup2; = 2 (2-k & sup2;) x & sup2; - 2K (1-2k) x - (1-2k) & sup2; -
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