Simple algorithm of 0.8 × (3.2-0.4) × 0.212.75 × (16-7.36-3.64) Simple algorithm of 0.8 × (3.2-0.4) × 0.212.75 × (16-7.36-3.64)

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• 1. Simple algorithm of 4 / 11-2 / 3 + 7 / 11
• 2. What is the simple algorithm of 6:1 + 1.6 + 3:2 + 3.75?
• 3. What is the specific operation method of 3 / 4 × 1 / 5 + 3 / 4 + 0.75 × 3 / 5-3 / 4
• 4. Simple algorithm for 5 / 7-5 / 9 * 5 / 7
• 5. 88888888x88888888: 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
• 6. How to solve 5x + 2x = 25 / 28-3 / 28
• 7. How to solve 4x + 18 = 5x equation
• 8. 49 + 0.009 * 0.5x = 18 + 0.04 * 0.5x the whole process of solving this equation
• 9. 0.8 is the solution of equation 5x + 14 = 18, Some people are not sure about this sentence, so they want to ask someone who is proficient in it
• 10. Solve the equation x + y = 58 y-4 / 5x = 4
• 11. Two fifths of a pile of coal is transported in the first time, and the remaining one-third is transported in the second time. A total of 120 tons are transported in the two times. How many tons are there in this pile of coal
• 12. To transport a pile of coal, 25% of this ton of coal was transported for the first time, 45% of this ton of coal was transported for the first time, and ()% of this ton of coal was transported for two times, with ()% remaining
• 13. There are five tons of coal in a pile, one fourth of which is transported in the first time, and one half of which is transported in the second time. How many tons of coal are transported in the two times?
• 14. A bulb marked with "220V 25W", the current of normal operation is____ The resistance of the bulb is____ .
• 15. Calculation by simple method 3 / 4 × 16 + 3 / 4 × 5-3 / 4 30.6 - (18.6 + 12 × 3 / 4) 4 / 7 △ 4 / 21 × x = 8 / 9 Solution ratio
• 16. It says on my refrigerator that the power consumption is 0.58 kwh / 24 hours, It says on my refrigerator that the power consumption is 0.58 kwh / 24 hours. Does it mean 0.58 kwh / day or hourly
• 17. (5-x) &# 178; + (7-2x) &# 178; = 25 the process of solving the equation
• 18. Symbol, unit and unit conversion of resistance
• 19. Let me ask you a question that you have answered before. Is it possible that the equation (2M2 + M-3) x ^ (M + 1) + 5x = 13 of X is a quadratic equation of one variable? The degree on X is m + 1 one (2m²+m-3)x^(m+1)+5x=13 If it is a quadratic equation of one variable, two conditions should be satisfied 1）m+1=2,m=1 2)2m²+m-3≠0 When m = 1, the above formula = 2 + 1-3 = 0, which does not meet the requirements So it can't be a quadratic equation of one variable two It's similar to the question M-1 = 2, then M = 3 Substituting M = 3 into 2m & # 178; + M-3, we get: 2m²+m-3=2×9+3-3=18≠0 So this could be a quadratic equation of one variable How does m + 1 become M-1 = 2, then M = 3 Substituting M = 3 into 2m & # 178; + M-3, we get: 2m²+m-3=2×9+3-3=18≠0 So this could be a quadratic equation of one variable
• 20. How to solve the problem that the circuit is changed from series connection to parallel connection, and the indication change of ammeter and voltmeter after moving the sliding rheostat in the circuit? It's better to have a problem-solving routine, The quantity is there, but because I don't understand it very well, the more I do it, the more confused I am.