If the equation AX2 + BX + C = 0 (a ≠ 0), a, B and C satisfy a + B + C = 0 and A-B + C = 0, then the root of the equation is () A. 1, 0b. - 1, 0C. 1, - 1D. Cannot be determined | Math enthusiast | Mathematical art

If the equation AX2 + BX + C = 0 (a ≠ 0), a, B and C satisfy a + B + C = 0 and A-B + C = 0, then the root of the equation is () A. 1, 0b. - 1, 0C. 1, - 1D. Cannot be determined

In this formula, if x = 1 is substituted into the equation, the left side will become a + B + C. from the known a + B + C = 0, it can be seen that when x = 1, the left and right sides of the equation are equal, that is, one root of the equation must be 1. Similarly, it can be judged that one root of the equation must be - 1. Then the root of the equation is 1, - 1

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