A calculation problem of mathematical fractional equation (x ^ 2 + 7x-8) / (x-1) + (x ^ 2 + X + 3) / (x + 2) + (2x ^ 2-x + 7) / (x + 3) = 4x, find the value of X I've solved it many times, but I can't get the answer

X ^ 2 + 7x-8 = (x-1) (x + 8) x ^ 2 + X + 3 = (x + 2) (x-1) + 52X ^ 2-x + 7 = (2x-7) (x + 3) + 28 original formula = (x + 8) + (x-1) + [5 / (x + 2)] + (2x-7) + [28 / (x + 3)] = 4x simplify to [5 / (x + 2)] + [28 / (x + 3)] = 0 multiply both sides of (x + 2) (x + 3) to get 5 (x + 3) + 28 (x + 2) = 0x = - 71 / 33

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