Application of fractional equation There are two roads from Beibei's home price to the school, each of which is 3km. The first road is a flat road, the second road has an uphill road of 1km, and the second road has a downhill road of 2km. Beibei's riding speed on the uphill road is vkm / h, on the flat road is 2vkm / h, and on the downhill road is 3vm / h 1. When taking the second road, what is the speed from home to school? 2. Please help him figure out which way to take and how long to take?

Your first question is wrong!
When taking the second road, Beibei from home to school, the uphill time T1 = 1 / V, downhill time T2 = 2 / 3V
So the total flowering time is (1 / V + 2 / 3V) = 5 / (3V) hours
The time to go flat is 3 / (2V) because 5 / (3V) > 3 / (2V),
So it takes less time to go on a level road, 5 / (3V) - 3 / (2V) = 1 / (6V) hours less

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