The pseudo fraction M & # 178; + 1 / M-1 is reduced to the sum of integral and true fraction

The original formula = (M & # 178; - 1 + 2) / (m-1)
=(m²-1)/(m-1)+2/(m-1)
=(m+1)(m-1)/(m-1)+2/(m-1)
=m+1+2/(m-1)

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