Given that a, B ∈ R, and A2 + AB + B2 = 3, let the maximum and minimum of a2-ab + B2 be m, m respectively, then M + M=______ ．

Let t = a2-ab + B2, from A2 + AB + B2 = 3 we can get A2 + B2 = 3-AB, from the properties of the basic inequality, (A2 + B2) ≤ 2Ab ≤ A2 + B2, then we can get ab-3 ≤ 2Ab ≤ 3-AB, the solution can get, - 3 ≤ ab ≤ 1, t = a2-ab + B2 = 3-ab-ab = 3-2ab, so 1 ≤ t ≤ 9, then M = 9, M = 1, M + M = 10, so the answer is 10

Given that a, B ∈ R, and A2 + AB + B2 = 3, let the maximum and minimum of a2-ab + B2 be m, m respectively, then M + M=______ ．

Given that a, B ∈ R, and A2 + AB + B2 = 3, let the maximum and minimum of a2-ab + B2 be m, m respectively, then M + M=______ ．

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