In the linear function y = (2m + 2) x + m, y decreases with the increase of X, and its image does not pass through the first quadrant, then the value range of M is () A. m>-1B. m<-1C. m=-1D. m<1

In the linear function y = (2m + 2) x + m, y decreases with the increase of X, and its image does not pass through the first quadrant, then the value range of M is () A. m>-1B. m<-1C. m=-1D. m<1

∵ in the linear function y = (2m + 2) x + m, y decreases with the increase of X, and its image does not pass through the first quadrant, ∵ 2m + 2 < 0m ≤ 0, the solution is m < - 1