The length of springs a and B is 1 m and 0.5 m, and the stiffness coefficients are 100 N / M and 150 n / m respectively. When they are connected in series and fixed on two columns with a distance of 2 m, the length of springs a and B is 100 N / M and 150 n / m respectively Find the length of a
k=k1k1/k1+k2=100*150/100+150=60N/m
Δs=2-1-1.5=0.5m
F=kΔs=60*0.5=30N
F1 + F2 = f, F1 = F2 (force equals reaction)
Δs1=F1/k1=30/100=0.3m
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