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Spring array o point in B, C between the amplitude of 10 cm, cycle 1 second, how to find the acceleration of the oscillator at B point! The ratio of the acceleration of the oscillator at point B to the acceleration at point P 4cm from point o!
The period formula of the spring oscillator: T = 2 * π root sign (M / k), M is the mass of the oscillator, K is the spring stiffness coefficient
The restoring force F = k * x, X is the displacement of the object from the equilibrium position
In this problem, it is known that the period is 1 second, and there is 1 = 2 * π radical (M / k)
So acceleration a = f / M = (K / M) * x = (2 * π) ＾ 2 * x
Because the amplitude is 10 cm, the ratio of the acceleration at point B to the acceleration at point P is ab: AP = 10:4 = 5:2
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