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A cup placed on a horizontal table has a mass of 0.2kg and a volume of 5 × 10 ∧ - 4 m #. Now fill the cup with water to find: (1) the mass of water in the cup; (2) the pressure of the cup on the table. (G is 10N / kg)
It is known that v = 5 × 10-4m3, ρ = 1.0 × 103kg / m3, M0 = 0.2kg, g = 10N / kg, s = 5 × 10-3m2
Find: (1) m water =? (2) P =?
（1）∵ρ=
m
V
The mass of water in the cup is m water = ρ v = 1.0 × 103kg / m3 × 5 × 10-4m3 = 0.5kg;
(2) The pressure of the cup on the table is p=
F
S
=
G
S
=
mg
S
=
(M0 + mwater) g
S
=
(0.2kg+0.5kg)×10N/kg
5×10−3m2
=1.4×103Pa．
Answer: (1) the quality of water in the cup is 0.5kg;
(2) The pressure of the cup on the table is 1.4 × 103pa
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