There is an object on a smooth horizontal table with a mass of 2kg. It is acted by two horizontal forces F1 and F2 at an angle of 120 ° to each other. The magnitude of the two forces is 10N. What is the acceleration of the object?

If the two components are equal and form an angle of 120 ° to each other, the solution is a = FM = 102m / S2 = 5m / S2 according to the parallelogram rule, where the resultant force is equal to the component force, f = 10N and F = ma. The acceleration direction is the same as f, that is, the direction of the bisector of the two components. A: the acceleration of this object is 5m / S2

RELATED INFORMATIONS

1. There is an object with a mass of 2kg on a smooth horizontal table. It is subjected to two forces in the horizontal direction which are 90 & ordm; angles to each other, both of which are 14 There is an object with a mass of 2kg on a smooth horizontal table. It is subjected to two forces in the horizontal direction which are 90 & ordm; angles to each other, both of which are 14N. What is the acceleration of this object? In what direction?
2. There is an object with a mass of 2kg on a smooth horizontal table. It is subjected to two forces at an angle of 60 degrees to each other in the horizontal direction. The magnitude of the two forces is 14N. How much is the acceleration of the object? The solution process is given
3. There is an object on the horizontal table with a mass of 2kg. It is subjected to two forces in the horizontal direction at 90 degrees to each other, both of which are 14N. What is the acceleration of the object and in what direction
4. On a smooth horizontal table, there is an object with a mass of 2kg. It receives two forces at an angle of 60. In the horizontal direction. The two forces are 14N. Find the acceleration of the object
5. An object with a mass of 2kg is still on a horizontal plane and starts to move under the action of a horizontal constant force of 10N. It moves 8m in 2S 1. Work done by horizontal constant force W 2. Average power of work done by horizontal constant force P The instantaneous power p'of the work done by the horizontal constant force at the end of 3.2 seconds How can FV get 400. Wrong,
6. A block of wood with mass m is still on the horizontal ground. Starting from t = 0, a horizontal constant force with size f acts on the block. At t = T1, the force F decreases What is the power? Why is it uniform acceleration?
7. A wooden block with mass m is still on a smooth horizontal ground. Starting from t = 0, a horizontal constant force with size f is applied on the wooden block. At t = T1, the power of force F is the answer. How to calculate f ^ 2 / m * t?
8. A block of wood with mass m is still on a smooth horizontal plane. Starting from t = 0, a horizontal constant force with size f is applied on the block. After t0 time, F A block of wood with mass m is still on a smooth horizontal plane. Starting from t = 0, a horizontal constant force with size f is applied on the block. The work w done by F in t0 and the power R of F at t0 are calculated
9. A piece of wood with mass m is still on a smooth horizontal plane. Starting from t = 0, a horizontal constant force of F is applied to the piece. At t = t, the power of F is () A. F2T2mB. F2T mC. F2T 2mD. F2T22m
10. The mass m of an object resting on a smooth horizontal surface is acted by a horizontal constant force F, and the instantaneous power is obtained in T seconds
11. There is an object with mass m = 0.5kg on the horizontal ground. A horizontal constant force F = 2.5n acts on the object and makes the object move from rest After a period of time, the action stops. The object continues to slide for a period of time and then stops. If the total distance of the object moving is s = 4m, the friction coefficient of the object is 0.2, and the work done by the force F (g = 10)
12. The object with mass m = 20 kg moves in a straight line along the horizontal plane under the action of constant horizontal external force F In 2S, f is opposite to the direction of motion, and in 4S, f is the same as the direction of motion, (g = 10m / S ^ 2). Calculate the dynamic friction coefficient between the object and the horizontal plane. (0s: v = 10m / S; 2S: v = 0; 4S: v = - 2m / s)
13. Under the action of constant force F, the object with mass m moves in a straight line with uniform acceleration along the horizontal plane, and the angle between F and the horizontal plane is θ Under the action of constant force F, the object with mass m moves along the horizontal plane with uniform acceleration. The angle between F and the horizontal plane is θ, and the dynamic friction coefficient between the object and the horizontal plane is μ
14. 2. The dynamic friction coefficient between the object with mass m and the horizontal plane on the horizontal plane is μ? 2. The dynamic friction coefficient between the object with mass m and the horizontal plane is μ. Under the action of the horizontal constant force F1, the object moves in a straight line at a constant speed on the horizontal plane. Now, if a constant force F2 equal to F1 is applied to the object, what is the maximum value of the combined external force acting on the object in the process of displacement s?
15. As shown in the figure, on a smooth horizontal plane, two objects AB move under the action of constant horizontal forces F1 and F2. Given that F1 > F2, what is the force a exerts on B
16. The object m moves on a smooth plane under the action of a constant force F along the horizontal direction, and a light spring with enough length is fixed in its forward direction When the object contacts the spring, it contacts and presses the spring to the shortest distance Block a decelerates when it contacts the spring Block B accelerates first and then decelerates when it contacts the block C when the velocity of the block is zero, the resultant force is zero D when the spring is in the maximum compression, the acceleration of the block is exactly equal to zero
17. The object m moves forward under the action of a constant force F in the horizontal direction on a smooth plane, and a spring with enough stiffness coefficient is fixed in its forward direction When the object contacts the spring, the a. Slow down immediately b. The external force on the object first decreases and then increases c. After a short period of time, the velocity of the object reaches the maximum and the acceleration is 0 d. When the spring is in the maximum compression, the acceleration of the object is 0 Thanks a lot!
18. Under the action of constant horizontal force F1, the object on the horizontal plane moves at a constant speed V1; if the force becomes a constant oblique force F2, the object moves at a constant speed v2 And the power of F1 and F2 are the same A F1=F2,V1>V2 B F1=F2,V1F1,V1>V2 D F2
19. When the water balance force F acts on the object with mass m, it means to move the displacement l along the direction of the force on a smooth horizontal plane. The work done by the constant force is W1, and then use the constant force Then the force is applied to the mass m (m)
20. The mass of the object on the horizontal plane is m, and the horizontal constant force F moves L; then the external force is removed, and the object moves 2L and stops?