A block of wood with mass m is still on the horizontal ground. Starting from t = 0, a horizontal constant force with size f acts on the block. At t = T1, the force F decreases What is the power? Why is it uniform acceleration?

First of all, when t = 0, the object is only subjected to the horizontal constant force of F, so that the external force of the whole body is F. therefore, according to Newton's second law, the object will uniformly accelerate in a straight line. Acceleration a = f / m
Secondly, because the object starts to move from rest, when t = T1, the displacement S = (1 / 2) a (T1) ^ 2 = (1 / 2) f (T1) ^ 2 / m,
Then the work of the object is w = FS = (1 / 2) (f ^ 2) (T1) ^ 2 / m,
Finally, according to the power definition formula P = w / T = = (1 / 2) (f ^ 2) (T1) ^ 2 / M (T1) = (1 / 2) (f ^ 2) (T1) / M = (f ^ 2) (T1) / 2m,

RELATED INFORMATIONS

1. A wooden block with mass m is still on a smooth horizontal ground. Starting from t = 0, a horizontal constant force with size f is applied on the wooden block. At t = T1, the power of force F is the answer. How to calculate f ^ 2 / m * t?
2. A block of wood with mass m is still on a smooth horizontal plane. Starting from t = 0, a horizontal constant force with size f is applied on the block. After t0 time, F A block of wood with mass m is still on a smooth horizontal plane. Starting from t = 0, a horizontal constant force with size f is applied on the block. The work w done by F in t0 and the power R of F at t0 are calculated
3. A piece of wood with mass m is still on a smooth horizontal plane. Starting from t = 0, a horizontal constant force of F is applied to the piece. At t = t, the power of F is () A. F2T2mB. F2T mC. F2T 2mD. F2T22m
4. The mass m of an object resting on a smooth horizontal surface is acted by a horizontal constant force F, and the instantaneous power is obtained in T seconds
5. What is the instantaneous power of an object resting on a smooth horizontal plane with a mass of M and subjected to a constant horizontal force F. for T seconds
6. There is a piece of wood on the horizontal ground with mass m, and the coefficient of sliding friction between it and the ground is μ. Under the action of the horizontal constant force F, the object starts to move from rest. After time t, the force F is removed, and the object moves forward for time 2T before it stops______ ．
7. Under the action of horizontal constant force, the object starts to move from rest on the horizontal plane. When the displacement is s, f is removed, and the object continues to move forward for 3S, and then stops moving. If the road condition is the same, the friction force and the maximum kinetic energy of the object are () A. f=F3B. f=F4C. EK=2Fs3D. EK=3Fs4
8. An object with mass m = 10kg is still on the horizontal plane and starts to move under the action of horizontal constant force F = 20n The acceleration of gravity g = 10m / S2 (1) if the horizontal plane is smooth, calculate the acceleration A1 and the velocity at the end of 2 seconds (2) if the horizontal plane is rough and the dynamic friction coefficient between the object and the horizontal plane is 0.1, calculate the acceleration A2
9. The stiffness coefficient of the spring is k = 20n / cm, with which a 20kg object is pulled to move on the horizontal plane. When the elongation of the spring is 4cm, the object just moves in a uniform straight line on the horizontal plane, and the speed is 4m / s. when the elongation of the spring is 6cm, the speed of the object moves for 2S, and then the distance that the pulling object can continue to slide is removed
10. A light spring with stiffness coefficient of 200N / m, the original length is 20cm, when its deformation is 10cm, the spring state and elastic force are () A. The spring must be in tension. B. the spring may be in compression. C. the spring force is 40nd. 20n
11. An object with a mass of 2kg is still on a horizontal plane and starts to move under the action of a horizontal constant force of 10N. It moves 8m in 2S 1. Work done by horizontal constant force W 2. Average power of work done by horizontal constant force P The instantaneous power p'of the work done by the horizontal constant force at the end of 3.2 seconds How can FV get 400. Wrong,
12. On a smooth horizontal table, there is an object with a mass of 2kg. It receives two forces at an angle of 60. In the horizontal direction. The two forces are 14N. Find the acceleration of the object
13. There is an object on the horizontal table with a mass of 2kg. It is subjected to two forces in the horizontal direction at 90 degrees to each other, both of which are 14N. What is the acceleration of the object and in what direction
14. There is an object with a mass of 2kg on a smooth horizontal table. It is subjected to two forces at an angle of 60 degrees to each other in the horizontal direction. The magnitude of the two forces is 14N. How much is the acceleration of the object? The solution process is given
15. There is an object with a mass of 2kg on a smooth horizontal table. It is subjected to two forces in the horizontal direction which are 90 & ordm; angles to each other, both of which are 14 There is an object with a mass of 2kg on a smooth horizontal table. It is subjected to two forces in the horizontal direction which are 90 & ordm; angles to each other, both of which are 14N. What is the acceleration of this object? In what direction?
16. There is an object on a smooth horizontal table with a mass of 2kg. It is acted by two horizontal forces F1 and F2 at an angle of 120 ° to each other. The magnitude of the two forces is 10N. What is the acceleration of the object?
17. There is an object with mass m = 0.5kg on the horizontal ground. A horizontal constant force F = 2.5n acts on the object and makes the object move from rest After a period of time, the action stops. The object continues to slide for a period of time and then stops. If the total distance of the object moving is s = 4m, the friction coefficient of the object is 0.2, and the work done by the force F (g = 10)
18. The object with mass m = 20 kg moves in a straight line along the horizontal plane under the action of constant horizontal external force F In 2S, f is opposite to the direction of motion, and in 4S, f is the same as the direction of motion, (g = 10m / S ^ 2). Calculate the dynamic friction coefficient between the object and the horizontal plane. (0s: v = 10m / S; 2S: v = 0; 4S: v = - 2m / s)
19. Under the action of constant force F, the object with mass m moves in a straight line with uniform acceleration along the horizontal plane, and the angle between F and the horizontal plane is θ Under the action of constant force F, the object with mass m moves along the horizontal plane with uniform acceleration. The angle between F and the horizontal plane is θ, and the dynamic friction coefficient between the object and the horizontal plane is μ
20. 2. The dynamic friction coefficient between the object with mass m and the horizontal plane on the horizontal plane is μ? 2. The dynamic friction coefficient between the object with mass m and the horizontal plane is μ. Under the action of the horizontal constant force F1, the object moves in a straight line at a constant speed on the horizontal plane. Now, if a constant force F2 equal to F1 is applied to the object, what is the maximum value of the combined external force acting on the object in the process of displacement s?