The object to be uniformly added passes through three points A.B.C in turn, XAB = XBC. It is known that the average velocity of the object in AB section is 3m / s, and that in BC section is 6m / s. The average velocity of the object at B point is 3m / s

The average speed of AB segment V1 '= (1 / 2) the average speed of BC segment V2' and ab = BC, so the time of passing AB segment is twice of that of passing BC segment. If the time of passing AB segment is 2T, then the instantaneous speed of passing BC segment is t, the instantaneous speed at the middle point of time = the average speed of T1 = t, and V1 = the average speed of AB segment = 3m / ST2 = 2.5t

RELATED INFORMATIONS

1. When an object is moving in a straight line with uniform acceleration, the average speed of the first half of the displacement is 3m / s, and the average speed of the second half is 6m / s, what is the speed when it passes through the middle position?
2. When an object is moving in a straight line with uniform acceleration, the average speed of the first half of the displacement is 3m / s, and the average speed of the second half is 6m / s, what is the speed when it passes through the middle position?
3. The average speed of the first half displacement is 3m / s, the average speed of the second half displacement is 6m / s, what is the average speed of the whole process How to calculate 4m / S? Why not 4.5m/s?
4. When an object moves eastward along a straight line, the average velocity of the first half displacement is 3m / s, and the average velocity of the second half displacement is 2m / s, then the average velocity of the whole displacement is () A. 2.5 m/sB. 1.2 m/sC. 2.4 m/sD. 2.3 m/s
5. When an object moves eastward along a straight line, the average velocity of the first half displacement is 3m / s, and the average velocity of the second half displacement is 2m / s, then the average velocity of the whole displacement is () A. 2.5 m/sB. 1.2 m/sC. 2.4 m/sD. 2.3 m/s
6. When an object moving in a straight line with uniform acceleration passes through points a, B and C in turn, the displacement SAB = SBC. It is known that the average velocity of the object in AB section is 1m / s, and the average velocity in BC section is 3m / s, then the instantaneous velocity of the object at point B is () A. 1.5m/sB. 2m/sC. 5m/sD. 2.5 m/s
7. When a particle with uniform acceleration passes through three points a, B and C continuously, it is known that ab = BC, and the average velocity of the particle in AB section is 3M/ When a particle moving in a straight line with uniform acceleration passes through three points a, B and C continuously, it is known that ab = BC, and the average velocity of the particle in AB section is 3m / s, and the average velocity in BC section is 6m / s, then the velocity of the particle in B is ()
8. When an object moves in a straight line with constant speed, its velocity is 3 m · S-1 at a certain time, and 9 m · S-1 after 1 s A. The displacement may be less than 5MB. The displacement may be less than 3mc. The acceleration may be less than 11m · s-2d. The acceleration may be less than 6m · S-2
9. When an object moves in a straight line with uniform speed change, the speed is 4m / s at a certain moment, and becomes 10m / s after 1s. What is the acceleration of the object? The answer is that when the initial velocity direction is positive, there are two cases of the end velocity. If the initial velocity is negative, the end velocity is positive, and 10 minus 4 = 14, the acceleration will be 14m / s Square, there will be one more case The acceleration is - 6m / s Square.
10. For an object moving in a straight line with uniform deceleration, the velocity at a certain moment is 8m / s, and after 1s, the velocity becomes 4m / s, then the displacement of the object passing through in 1s
11. When an object moving in a straight line with uniform acceleration passes through points a, B and C in turn, the displacement XAB = XBC. It is known that the average velocity of the object in AB section is 3m / s, and that in BC section is 6m / s, then the instantaneous velocity of the object at point B is () A. 4 m/sB. 4.5 m/sC. 5 m/sD. 5.5 m/s
12. When an object moving in a straight line with uniform acceleration passes through points a, B and C in turn, it is known that ab = BC, and the average velocities of AB and BC sections are V1 = 3m / s and V2 = 6m / s respectively (1) What are the instantaneous velocities VA, VB and VC of an object passing through points a, B and C? Why can't we use the simultaneous formula (VA + VB) / 2 = 3, (VB + VC) / 2 = 6, (VA + VC) / 2 = VB to calculate VB equal to 4.5? Please tell me why it's not right to do so
13. A small ball with a mass of 1 kg is thrown horizontally at an initial speed of 3 M / s, and the landing speed is 5 m / s, regardless of the resistance, g = 10 m / S ^ (1) How high is the throw point from the ground? (2) What is the instantaneous power of gravity when the ball is about to land?
14. (Physics of senior two) an object is thrown horizontally at the speed of 3m / s, and the landing speed is 5m / s. The flight time and displacement of the object are calculated
15. When an athlete puts a shot, it is 5 / 3M above the ground at the first time of putting the shot. The landing point of the shot is 10m away from the corresponding point on the ground at the first time of putting the shot. The highest point of the shot is 3M above the ground. It is known that the route of the shot is a parabola. The analytical formula of the parabola can't be solved
16. Dissolve two shot with radius of 3M and 5m to make a bigger shot. What is the radius of the big shot (accurate to 0.1cm)?
17. A small ball is thrown horizontally at the speed of 3m / s, and its landing speed is 5m / s. The time and displacement of the ball in the air are calculated
18. When an object is thrown horizontally from a certain height, the initial velocity is 3m / s, the landing velocity is 5m / s, and the air resistance is not considered
19. The same object moves at the speed of V1 for the first time and V2 for the second time on the same plane (V1 > V2). Why is the pulling force the same when the moving speed is different?
20. Two small balls are fixed at both ends of a rod with length L, and make a circular motion around a point o on the rod. The speed of small ball 1 is V1, and the speed of small ball 2 is v2. Calculate the distance from O to 2