When an object moving in a straight line with uniform acceleration passes through points a, B and C in turn, the displacement SAB = SBC. It is known that the average velocity of the object in AB section is 1m / s, and the average velocity in BC section is 3m / s, then the instantaneous velocity of the object at point B is () A. 1.5m/sB. 2m/sC. 5m/sD. 2.5 m/s

(1) According to the law of uniform acceleration linear motion, we can get: vb2-va2 = 2al2vc2-vb2 = 2al2va + VB2 = V1 = 1m / SVB + vc2 = V2 = 3m / s, we can get: VB = 2.5m/s, so we choose: D

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