The car runs on the road at a speed of 10m / s, and then decelerates at a speed of 2m / S 2 after braking. The speed at the end of 4S and the displacement of the car in 8s after braking are calculated

If the time t0 = 0 − v0a = − 10 − 2S = 5S, then the speed at the end of 4S after braking is v = V0 + at = 10-2 × 4m / S = 2m / s. The displacement within 8s is equal to the displacement within 5S, then x = v02t0 = 102 × 5m = 25m. A: the speed at the end of 4S after braking is 2m / s, and the displacement within 8s is 25m

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