When an object moves in a straight line with uniform deceleration, the acceleration is 2m / s. After two seconds of movement, its final velocity is half of its initial velocity. The displacement of the object in this 2S and the distance from the object to stop are calculated

The initial velocity is v0
The solution of VT = V0 at VT = 0.5v0 is V0 = 8m / s and VT = 4m / s
Displacement in 2 seconds s = v0t-0.5at ^ 2 = 8 * 2-0.5 * 2 * 4 = 12m
The moving distance after stationary is s = V0 ^ 2 / 2A = 64 / 4 = 16m

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