If the acceleration is 2m / S ^ 2 and the displacement is 1 / 4 of the whole displacement two seconds before the motion stops, then the initial velocity of the object is Don't use image method

This problem can be easily solved by practical image method
It can be done without image method
However, this topic is a little special, you can use the reverse method
It is because 1 / 4 of the displacement is moved within 2S before the motion stops, and the acceleration is known
Therefore, it can be imagined that the displacement of an object in the first two seconds is 0.25 times of the total distance
So, 0.25s = 0.5 * 2 * 2 * 2
S=16M
Then VT * vt-v0 * V0 = 2As is used
Calculated VT = 8m / s
That is the initial velocity of uniform deceleration motion

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