When an object moves in a straight line with constant speed, the velocity at a certain moment is V1 = 4m / s. after t = 2S, the velocity becomes V2 = 8m / s, and the acceleration a of the object is calculated

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• 1. When an object moves in a variable speed linear motion, the velocity is 4 m / s at a certain moment, and the velocity after 2 s is 4 m / s. if the acceleration of the object is constant within 2 s, then the acceleration of the object is constant A / may be equal to 0 B / may be less than 4m / S C / must be 4 m / s D / may be greater than 4m / s
• 2. The initial velocity of the object is V0 = 5m / s, the initial acceleration is A1 = 4m / s # 178;, and the acceleration becomes A2 = 2m / s # 178; after moving for 2S What are the velocities at the end of 1s, 2S, 3S and 4S? The acceleration a decreases but the velocity V increases. Why?
• 3. When an object is accelerating uniformly, the initial velocity is 0.5m/s, and the displacement in the second second second is 4m more than that in the first second It can be calculated with △ x, but why can't it be calculated with x = v0t + 0.5at ^ 2
• 4. The displacement of an object in the second second second is 10 m,
• 5. When an object moves in a straight line with a uniform acceleration of 2m / s and the displacement in the second second is 12M, the initial velocity of the object is
• 6. After braking, the moving car moves in a straight line with uniform deceleration and stops in 3.5 seconds. The ratio of the displacement that it passes in 1 second, 2 seconds and 3 seconds after braking is () A. 1：3：5B. 3：5：7C. 1：2：3D. 3：5：6
• 7. If the displacement in the second second second after braking is 6.25m (the braking time is more than 2S), then (1) what is the acceleration of the vehicle? (2) What is the displacement of vehicle passing through in 6 seconds after braking?
• 8. What is the displacement ratio of a car moving along a straight line after braking, decelerating and taxiing evenly and stopping in 3.5 seconds
• 9. If the displacement is 6 meters in the first second and 2 meters in the last second before stopping, then: (1) during the whole deceleration If the displacement in the first second is 6 meters and that in the last second before stopping is 2 meters, then: (1) what is the displacement of the car in the whole deceleration process? (2) how much time does the whole deceleration process share?
• 10. After braking, the car moving at a uniform speed of 10m / s moves in a straight line with uniform deceleration. The displacement within 2S after braking is 6.25m, and that within 6S after braking is 6.25m
• 11. When an object is moving in a straight line with uniform speed change, the velocity is 4m / s and 178; at a certain time. After 2 seconds, the velocity becomes 8m / s and 178; to calculate the acceleration of the object
• 12. A. Car B stops at the same place. At a certain moment, car a starts at a constant acceleration of 2m / S ^ 2. After 2 seconds, car B starts at a constant acceleration of 4.5m/x ^ 2 in the same direction (1) How long does car B leave to catch up with car a? (2) Before car B overtakes car a, what is the maximum distance between the two cars? Draw a V-T image
• 13. When an object moves in a variable speed linear motion, the velocity is 4 m / s at a certain moment, and becomes 10 m / s after 2 seconds, then the average acceleration of the object in these 2 seconds is less than 10 m / s? Why? I know the answer 3m / S2 and 7m / s2
• 14. When the acceleration is 2 m / S2 and the displacement is 20 m in the first four seconds, the initial velocity is 0___ M / s, the initial velocity in the second second second is___ m/s The acceleration is 2m / S2 and the displacement is 20m in the first four seconds Then the initial velocity is______ m/s, The velocity at the beginning of the second second is______ m/s, The final velocity in 4S is______ m/s, The ratio of the first 2 s displacement to the second 2 s displacement is 0______
• 15. The object is moving in a straight line with uniform acceleration, the acceleration is 4m / S2, and the displacement is 12m within 2S
• 16. A particle starts at rest, first makes a period of uniform acceleration linear motion with the acceleration A1 & nbsp; for a period of time, then makes a uniform deceleration linear motion with the acceleration A2 until it stops. The total time of the particle motion is t, and the total displacement of the particle is calculated
• 17. The car starts to make a uniform acceleration linear motion with the acceleration of A1 from static, and after a period of time, makes a uniform motion with the acceleration of A2. The time of the whole process is t. please write down the detailed process of solving the problem. It is also useful to discuss the size of A2 instead of the direction?
• 18. The car starts to make a uniform acceleration linear motion with the acceleration A1 from the standstill, and then accelerates with the acceleration A2 after a period of time The car starts to make uniform acceleration linear motion with the acceleration of A1 from standstill, and then makes uniform deceleration linear motion with the acceleration of A2 after a period of time. It comes to a standstill after a total distance of L, so as to find the total time of car motion There should be a process. Thank you
• 19. The motorcycle starts from a standstill, runs for a certain distance with the acceleration of A1 = 1m / S2, then moves at a constant speed, and then decelerates with the acceleration of A2 = - 4 / S2 until it stops. It takes 1440m and 100s to walk. It is not necessary to solve the maximum speed VM twice in this process
• 20. The motorcycle starts from standstill, runs for a distance with the acceleration of A1 = 1m / S2, then makes a constant speed movement, and then makes a constant deceleration movement with the acceleration of A2 = - 4 / S2 until it stops. The motorcycle has walked 1440m in total and lasted for 100s. The maximum speed of the motorcycle in this process is calculated