What is the displacement ratio of a car moving along a straight line after braking, decelerating and taxiing evenly and stopping in 3.5 seconds

For example, there is a formula: V end = V beginning + at, so V beginning = - at = - 3.5A. Bring this formula into: S = V beginning * t + (1 / 2) * a * t * t, get: S1 = - 3a, S2 = - 5A, S3 = - 6A (a is negative), so. 3:5:6 add

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1. If the displacement is 6 meters in the first second and 2 meters in the last second before stopping, then: (1) during the whole deceleration If the displacement in the first second is 6 meters and that in the last second before stopping is 2 meters, then: (1) what is the displacement of the car in the whole deceleration process? (2) how much time does the whole deceleration process share?
2. After braking, the car moving at a uniform speed of 10m / s moves in a straight line with uniform deceleration. The displacement within 2S after braking is 6.25m, and that within 6S after braking is 6.25m
3. After entering the station, the car starts to brake and decelerate in a straight line. In the first second, the displacement is 9 m and 7 m respectively After entering the station, the car starts to brake and make a uniform deceleration linear motion. The displacement in the first second is 9m and 7m in turn. Then what is the displacement in the sixth second after braking? Why can we use the displacement difference 2m to get 9,7,5,3,1,0m? Why is it 0m in the end
4. Because of the brake, the car starts to make uniform deceleration linear motion at the speed of 10m / s. if the average speed in the first second is 9m / s, what is the displacement of the car in the first 7S?
5. When a bus comes into the station, it starts to brake and make a uniform deceleration linear motion. The displacement in the first second and the second second is 9m and 7m respectively, then the displacement in the sixth second after braking is () A. 20 mB. 24 mC. 25 mD. 75 m
6. The average speed in the third second is 9 m / s. find (1) the acceleration of the uniform deceleration of the car (2) the displacement of the car in 10 s
7. The car starts to brake at the speed of 10m / s, the acceleration is 2m / S2, and the displacement ratio of 3S, 2S and 1s before stopping is calculated
8. When a car moves forward at a speed of 10m / s and the acceleration is 2.5m/s2 after braking, what is the displacement in 3S? What is the displacement within 10 seconds after braking?
9. A car moves forward at a constant speed of 10m / s. after braking, the acceleration is 2.5m/s and the displacement within 3S
10. A car stops and starts to run at 3 meters per second, when a bicycle comes at a constant speed of 6 meters per second How long does it take for the car to catch up with the bicycle? What is the distance between the two cars?
11. If the displacement in the second second second after braking is 6.25m (the braking time is more than 2S), then (1) what is the acceleration of the vehicle? (2) What is the displacement of vehicle passing through in 6 seconds after braking?
12. After braking, the moving car moves in a straight line with uniform deceleration and stops in 3.5 seconds. The ratio of the displacement that it passes in 1 second, 2 seconds and 3 seconds after braking is () A. 1：3：5B. 3：5：7C. 1：2：3D. 3：5：6
13. When an object moves in a straight line with a uniform acceleration of 2m / s and the displacement in the second second is 12M, the initial velocity of the object is
14. The displacement of an object in the second second second is 10 m,
15. When an object is accelerating uniformly, the initial velocity is 0.5m/s, and the displacement in the second second second is 4m more than that in the first second It can be calculated with △ x, but why can't it be calculated with x = v0t + 0.5at ^ 2
16. The initial velocity of the object is V0 = 5m / s, the initial acceleration is A1 = 4m / s # 178;, and the acceleration becomes A2 = 2m / s # 178; after moving for 2S What are the velocities at the end of 1s, 2S, 3S and 4S? The acceleration a decreases but the velocity V increases. Why?
17. When an object moves in a variable speed linear motion, the velocity is 4 m / s at a certain moment, and the velocity after 2 s is 4 m / s. if the acceleration of the object is constant within 2 s, then the acceleration of the object is constant A / may be equal to 0 B / may be less than 4m / S C / must be 4 m / s D / may be greater than 4m / s
18. When an object moves in a straight line with constant speed, the velocity at a certain moment is V1 = 4m / s. after t = 2S, the velocity becomes V2 = 8m / s, and the acceleration a of the object is calculated
19. When an object is moving in a straight line with uniform speed change, the velocity is 4m / s and 178; at a certain time. After 2 seconds, the velocity becomes 8m / s and 178; to calculate the acceleration of the object
20. A. Car B stops at the same place. At a certain moment, car a starts at a constant acceleration of 2m / S ^ 2. After 2 seconds, car B starts at a constant acceleration of 4.5m/x ^ 2 in the same direction (1) How long does car B leave to catch up with car a? (2) Before car B overtakes car a, what is the maximum distance between the two cars? Draw a V-T image