After landing, the plane moves in a straight line with a constant deceleration at an acceleration of 6m / S2. If the landing speed is 60m / s, the distance of the plane taxiing 12s after landing is () A. 288 mB. 300 mC. 450 mD. 400 m

The time to decelerate to zero t0 = 0 − v0a = − 60 − 6S = 10s ＜ 12s, then the displacement within 12s is equal to the displacement within 10s, x = 0 − v022a = − 3600 − 12m = 300m

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