How to prove that the instantaneous velocity in the middle of a process is equal to the average velocity of the process, that is, vzhong = 1 / 2 [V0 + VT]

How to prove that the instantaneous velocity in the middle of a process is equal to the average velocity of the process, that is, vzhong = 1 / 2 [V0 + VT]

We can use the image method
Draw the V / t image, and then you can follow the ladder
The median line of a shape is equal to half the length of the top and bottom
If the initial velocity is zero and the image is a triangle, the conclusion still holds