A maintenance team took a car along the road maintenance line, agreed to forward as positive, backward as negative, one day from the o to the end of work The route (unit: km) is + 10, - 3, + 4, + 2, - 8, + 13, - 2, + 12, + 8, + 5 (1) How far is the closing time from o? (2) If the fuel consumption per kilometer is 0.2 liter, how much is the total fuel consumption from O to the end of work? Formula | Math enthusiast | Mathematical art

A maintenance team took a car along the road maintenance line, agreed to forward as positive, backward as negative, one day from the o to the end of work The route (unit: km) is + 10, - 3, + 4, + 2, - 8, + 13, - 2, + 12, + 8, + 5 (1) How far is the closing time from o? (2) If the fuel consumption per kilometer is 0.2 liter, how much is the total fuel consumption from O to the end of work? Formula

（1）10-3+4+2-8+13-2+12+8+5
=10-3+4+13+12+5
=44-3
=41 (km)
（2）0.2 x（10+3+4+2+8+13+2+12+8+5）
=0.2 x 67
=13.4 (L)
A: it's 41 kilometers away from the ground at the end of the work, and the total fuel consumption is 13.4 liters

RELATED INFORMATIONS

1. When someone goes from a to B, he moves at a speed of 2km per hour. He advances one meter, then retreats two meters, then advances three meters, retreats four meters Q: Someone goes from a to B at a speed of 2km per hour. He advances one meter and then retreats two meters. He advances three meters and retreats four meters. How far is he from a after 10 minutes
2. When the particle moves along a straight line, its acceleration is a = 2-3T (SI). If t = 2S, the particle is located at x = 1m, v = 2m / s, find 1, the velocity of the particle; 2. The equation of motion of a particle
3. A particle starts to move from rest with an acceleration of 1 m / S2. Some people say that its velocity at the end of the first second is 1 m / s and that at the end of the second is 2 m / s. therefore, its displacement in the first second is 1 m and that in the second is 2 M. do you think that's right? Why?
4. A particle starts to move in a straight line from its rest. In the first second, it moves at an acceleration of a = 1 m / S & sup2; in the second second, it moves at an acceleration of a '= - 1, and in the third, it moves at an acceleration of a = 1 m / S & sup2 =What is the total displacement of this particle after 100 s of repeated acceleration in the fourth second?
5. The motorcycle starts from standstill, runs for a distance with the acceleration of A1 = 1m / S2, then makes a constant speed movement, and then makes a constant deceleration movement with the acceleration of A2 = - 4m / S2 until it stops. The motorcycle has walked 1440m in total and lasted for 100s. The maximum speed of the motorcycle in this process is calculated
6. A vehicle weight 5T, rated power 80kW, acceleration a = 1m / S2 for uniform acceleration linear motion, the resistance of the vehicle is 0.06 times of the vehicle weight, G take 10m / S2, calculate, 1. Analyze the change of traction and engine power during the process of constant acceleration from static to constant speed 2. How long can the car maintain a uniform acceleration linear motion 3. The average power of the car in the process of uniformly accelerating linear motion 4. Instantaneous power at the end of 10s acceleration 5. Maximum speed
7. When a vehicle with a mass of 5t starts from a standstill and runs along a straight road with an acceleration of 1m / S2, the resistance of the vehicle is known to be 1000N. What is the traction force of the vehicle? What is the power of the car at the end of 10s? How much work does the external force do to the car during this period?
8. The car starts to move in a straight line with uniform acceleration from standstill, the acceleration is 0.1, and the path is a and B points 150m apart, sharing 10s What is the speed of the tram passing through point a and point B?
9. The length of the bridge is 150m. The time of the whole train passing through the bridge is calculated as follows: (1) the time of the whole train passing through the bridge. (2) the time of the whole train passing through the bridge
10. The weight of a vehicle is 5T, the rated power is 80kW, the acceleration a = 1m / S2 is used for uniform acceleration linear motion, the resistance of the vehicle is 0.06 times of the vehicle weight, G is taken as 10m / S2 To find the average power of the car in the process of uniformly accelerating linear motion
11. The forward and backward trajectory of a car with full wheels Is the track of forward and backward motion the same circle when the car is full of wheels to the left,
12. When the car moves forward or backward, turn the steering wheel to the left or right, and the direction of the front and rear of the car is the same or the opposite
13. Motor vehicle D is forward, what is backward
14. (1 / 2) the car starts to move at an acceleration of 1 meter every second. At 20 meters behind the car, while the car starts to move, someone starts to ride a bicycle at the same time (1 / 2) the car starts to move forward at an acceleration of 1 meter per second. 20 meters behind the car, while the car starts to move, someone starts to chase the car at a constant speed of 6 meters per second. Can he catch up with the car (1 / 2) the car is driving at the speed of 18 meters per second. When the driver suddenly finds an obstacle in front of him, he brakes immediately. Assuming that the acceleration is 3 meters per second after braking, he decelerates evenly, and calculates the sliding distance of the car in 10 seconds (2 / 2)?
15. The bicycle chases the car in front at the speed of 5 m / s. when it is 20 meters away from the car, the car starts at the acceleration of 1 m / s Can the bicycle catch up with the car
16. The car starts to move at an acceleration of 1 meter per second from a standstill. At 20 meters behind the car, while the car starts to move, someone starts to catch up at a constant speed of 6 meters per second on his bicycle. Can he catch up? What is the minimum distance between people and the car?
17. The car starts to move in a straight line at a constant acceleration of a = 1m / S & sup2; from a standstill, and the people at a distance of 25m behind the car chase the car at a constant speed of V = 6m / s, Can catch up with you? We need to calculate the process
18. Width L = 300m, river velocity V1 = 3m / s, ship velocity V2 = 5m / s in still water, find: (1) what is the shortest time for the boat to cross the river? What is the course of the boat? (2) what is the shortest displacement for the boat to cross the river? What is the time for the boat to cross the river?
19. The width of the river is d = 300 m, the velocity of the river is V1 = 1 m / s, the velocity of the ship in still water is V2 = 3 M / s, and the course of the ship forms a 30 degree angle with the upstream bank How long does it take for it to cross the river (3) How can the course reach the opposite shore (4) How to cross the river in the shortest time, (2) 320m upstream （3）cosθ=1/3 (4) The bow is always perpendicular to the other side of the river, t = 100s
20. When the width of the river is 420m, the speed of the ship in still water is 4m / s, and the flow speed is 3m / s, the shortest time for the ship to cross the river is? The answer is 105s, hope to have a complete process