When someone goes from a to B, he moves at a speed of 2km per hour. He advances one meter, then retreats two meters, then advances three meters, retreats four meters Q: Someone goes from a to B at a speed of 2km per hour. He advances one meter and then retreats two meters. He advances three meters and retreats four meters. How far is he from a after 10 minutes

Unify units first
It takes 1 / 2000 = 1 / 2000 hours = 3 / 100 minutes to move 1 meter
The speed is 100 / 3 M / min per minute
The movement time of each part of the journey constitutes an arithmetic sequence
3/100 6/100 9/100...
Sum of sequence Sn = 3 (1 + n) n / 200
Let's set up the 10th minute when the person is in the M-segment movement
Sm-1

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