If the difference between the two equations x ^ 2 + 2x + K + 1 = 0 is 2 √ 3, then the value of K is

So: (x1 + x2) = - 2 (x1 + x2) & sup2; = 4 (x1) & sup2; + 2 (x1) (x2) + (x2) & sup2; = 4 (x1) & sup2; - 2 (x1) (x2) + (x2) & sup2; = 4 (x1) & sup2; + 4 (x1) (x2) = 4 (x1 - x2) & sup2; + 4 (x1) (x2) = 4 because: X

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