Given that the square of equation 2x + 3x + m is equal to two real roots of 0, one of which is twice of the other, we can help you to find the value of M

Let a real number root be a, and the other be 2a, 2A + 3A + M = 0. ① 2 (2a) + 3 (2a) + M = 0. ② simplify to 8A + 6A + M = 0. ③ - ① to 6A + 3A = 0 (6a + 3) a = 0, a = 0 or a = - 1 / 2 a = 0. If X1 = - 1 / 2 x2 = - 1, M = 1 can be obtained

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