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設一個實數根為a,另一個為2a 2a+3a+m=0①2(2a)+3(2a)+m=0②②化簡得:8a+6a+m=0③③-①得:6a+3a=0(6a+3)a=0 a=0或a=-1/2 a=0舍去x1=-1/2 x2=-1可求得m=1
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