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由於本題並沒有要求方程一定是一元二次方程,所以應分兩種情形: 情形一:方程是一元一次方程,則 m=0時,方程只有一個實數根:x=1/2; 情形二:方程是一元二次方程,則 二次項係數m≠0,且判別式△=0,即 △=(-2)^2-4*m*1=0 即4-4m=0,解得:m=1. 綜上,關於X的方程mx^2-2x+1=0,只有一個實數根,則m的值是0和1.
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