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設關於x的方程2x2+5x+p-3=0的另一根是x2,則-4+x2=-52,解得,x2=32;∵關於x的方程2x2+5x+p-3=0的一個根是-4,∴2×(-4)2+5×(-4)+p-3=0,即9+p=0,解得p=-9.∴方程的另一個根是32、p的值是-9.
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