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答: 方程kx²;+(2k-1)x+k-1=0只有整數根 利用十字相乘法分 kx k-1 * x 1 方程化為: (kx+k-1)(x+1)=0 1)k=0時:x=-1,滿足題意 2)k不為0時:x1=-1,x2=(1-k)/k=1/k-1為整數 所以:k=1或者k=-1 綜上所述,k=0或者k=-1或者k=1
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