![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
1、4+75/25-2+1/2= 2、（5/3-1）-（1/3-1/6）+5/10-1= 3、5-（13/6+11/8-17/12）-（2+1/6）= 4、5/12-【（8/5+11/30-8/15）-（17/10-7/20）】= 5、4/3-【3/4-（2/3-2/7）+3/14】+1+1/6-3/2= The first answer is: 11 / 2 The second answer is: 0 The third answer is: 17 / 24 The answer to the fourth question is: 1 / 3 The answer to the fifth question is: 5 / 12
1、4+75/25-2+1/2=4+3-2+1/2=5+1/2=11/22、（5/3-1）-（1/3-1/6）+5/10-1=2/3-1/6+1/2-1=1/2+1/2-1=03、5-（13/6+11/8-17/12）-（2+1/6）=5-2-(13/6+1/6)+(17/12-11/8)=3-7/3+1/24=2/3+1/24=17/244、5/12-【（8/5+11...
RELATED INFORMATIONS
- 1. There is a square lawn with a side length of 40 meters. The side length has been increased by 10 meters and expanded into a larger lawn. How many square meters has the lawn area increased
- 2. When a kettle with a mass of 0.3KG is filled with water, the total mass is 0.8kg, and when it is filled with another liquid, the total mass is 0.7kg, then the density of this liquid is () A. 1.4×103kg/m3B. 0.875×103 kg/m3C. 0.8 kg/m3D. 0.8×103 kg/m3
- 3. If a regular n prism has 22 faces, and the sum of the lengths of all sides is 100cm, and the side length of the bottom is 5cm, what is the area of one side of the prism?
- 4. 2(sinx)^2-sinxcosx-(cosx)^2=1 X solution set is required
- 5. Put a circular scissors together to form an approximate rectangle. The length of the rectangle is 6.28 decimeters. What is the area of the circle? What is the perimeter? Big brother“ Beautiful women? Brother is OK
- 6. Data x1, X2 The mean of XN is x, the variance is S & # 178, then 2x1 + 3,2x2 + 3 2xn + 3 mean and variance the 2x + 3,4s & # 178 I chose; Did I choose the right question for the final exam today? Don't beat me up
- 7. The circumference of a rectangular piece of paper is 80cm, and the ratio of length to width is 5:3. If you cut it into the largest square piece of paper, what is the area of the square piece of paper?
- 8. If the average of a set of data x1, X2, X3,... Xn is 5, then the average of data 3x1 + 5, 3x2 + 5, 3x3 + 5,... 3XN + 5 is 5
- 9. The classroom is paved with 1800 tiles, 40 cm long, 20 cm wide and 1 cm thick. How many square meters is the area of the classroom
- 10. 1.6/1 hour = () minutes 2.6.08 cubic meters = () cubic meters () cubic decimeters 3. A cylinder and a cone are of equal height and equal base. The sum of their volumes is 48 cubic centimeters, and the volume of this cone is () cubic centimeters 4. The side area of the cylinder is fixed, and the radius of the bottom is in direct proportion to () 5 ratio: 4.2:3 5cm: 30m Simplification ratio: 192:645.25:356/1:9/1 15 / 8:25 / 12 3T: 150kg Solution equation: 1.5x + 24 = 89 9 / 2 × 3 + 4x = 12 / 11 14 / 3x + 21 / 13X = 28 / 15 To find the ratio, simplify the ratio and solve the equation,
- 11. The circumference of a rectangular piece of paper is 160cm, and the ratio of length to width is 5:3. If it is cut into the largest square piece of paper, what is the area of the square piece of paper?
- 12. In a long-distance race, the athletes run 5 kilometers away from the starting point and return to the starting point. The leading athlete runs 320 meters per minute, and the last athlete runs 305 meters per minute. How many points do the two athletes meet after the start? How many meters are there from the return point when they meet?
- 13. If the perimeter of a parallelogram is equal to 50cm, then the length of each diagonal must be less than () cm
- 14. On the equation KX & # 178; + (2k-1) x + k-1 = 0 of X, there is only integer root. K is an integer. Find the value of K
- 15. Given that the two real roots of equation x2 + KX + 6 = 0 are x1, X2, and the two real roots of equation x2-kx + 6 = 0 are X1 + 5, X2 + 5, then the value of K is equal to () A. 5B. -5C. 7D. -7
- 16. If the equation | X-1 | - KX = 0 has and only has one positive real root, then the value range of real number k is______ ．
- 17. The root of the quadratic equation of one variable x-4 = 0 is
- 18. On the quadratic equation (a-6) with one variable of X, the square of x-8x + 9 = 0 has real roots. Find the maximum integer value of A
- 19. If the equation 5 + m / (X-2) + 1 = 1 / (2-x) about X has no solution, then M=
- 20. On a root of the equation x ^ 2-5x + M-1 = 0 of X It is known that a root of the equation x ^ 2-5x + M-1 = 0 about X and a root of the equation x ^ 2 + 5x-m + 1 = 0 about X are opposite numbers, and the value of M is obtained Let a root of equation x ^ 2-5x + M-1 = 0 be a, and a root of equation x ^ 2 + 5x-m + 1 = 0 be - A, then a^2-5a+m-1=0, a^2-5a-m+1=0 If you want to reduce 2m-2 to 0, then M = 1