Find the area of the figure enclosed by parabola y2 = 8x (Y > 0) and straight line x + y-6 = 0 and y = 0

Find the area of the figure enclosed by parabola y2 = 8x (Y > 0) and straight line x + y-6 = 0 and y = 0

Let the figure area be s, s = ∫ 2022 · xdx + ∫ 62 (6 − x) DX (4 points) = 432x32 | 20 + (6x − 12x2) | 62 (8 points) = 163 + 8 = 403 (12 points)