2011 minus half of it, then minus the remaining 1 / 3, then minus the remaining 1 / 4, and so on, until finally minus the remaining 1 / 2011 Find the last remaining number

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• 1. 2011 minus 1 / 2 of it, then minus the remaining 1 / 3, then minus the remaining 1 / 4, and so on, until finally minus the remaining 1 / 2011, find the last remaining number?
• 2. Use 2013 to subtract its 12, then subtract the remaining 13, then subtract the remaining 14 And so on, until the last minus the remaining 12013, the final result is______ ．
• 3. 2014 minus 1 / 2 of it, minus the remaining 1 / 3, minus the remaining 1 / 4, and so on, until the end Hurry, hurry, hurry,
• 4. 1. 2013 minus 1 / 2, and then minus the remaining 1 / 3, and then minus the remaining 1 / 4, and so on, all the way minus the remaining 1 / 2013, to find the final remaining number 2. Fold a rope into 3 pieces and cut it from the middle with scissors to get the rope () A. 3 b.4 C.5 d.6 3. On the number axis, the distance between two points B representing numbers x and - 1 can be expressed as_____________ . If iabi = 3, find the value of X
• 5. 2008 - half of it, minus the remaining third, minus the remaining quarter, and so on. Until the end, minus the remaining 208 Come on, let's go
• 6. 1999 subtracts its 12, then subtracts the remaining 13, then subtracts the remaining 14, and so on, until finally subtracts the remaining 1 / 1999, finds the last remaining number
• 7. A rope is 99 meters long, use half of it, then use the remaining 1 / 3, and then use the remaining 1 / 4. And so on, until the remaining 1 / 99 is used, how many meters are left in the end?
• 8. Cut 1 / 2 of the 1000 meter iron wire for the first time, and then cut the remaining 1 / 3 for the second time, and so on, until the remaining 1 / 1000 is cut, and then calculate the length of the remaining iron wire It's better to have ideas and process!
• 9. (1 / 100-1) (1 / 99-1) (1 / 98-1). (1 / 3-1) (1 / 2-1)
• 10. Calculation: two thirds + one and a half, - (- 1 and a third) | - 2 | - (- 2.5) -1-4 | 24 + (- 14) + (- 16) + 8 —40—28—（—19）+（—24）
• 11. 2010 minus one-half of it, and then minus the remaining one-third, in minus the remaining one-quarter, and so on, one minus the next one-third of 2010, find the most 2010 minus one-half of it, and then minus the remaining one-third, in the subtraction of the remaining one-fourth, and so on, one minus the next 20 urgent 10 percent, find the final remaining number? Urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent urgent
• 12. Subtract 1 / 2 of 2007, then subtract the remaining 1 / 3, then subtract the remaining 1 / 4... And so on until you subtract the remaining 1 / 2007 Second, we know that a + B + C = 0, and a + B + C = 0 Third: if the square of | X-1 | + | y + 2 | + (Z-3), find the value of formula (x + 1) (Y-2) (Z-3)
• 13. Subtract 12 from 2009, the remaining 13, the remaining 14, the remaining 15, and so on, until you subtract the remaining 12009______ ．
• 14. (1 minus 1 / 2) plus (1 / 2 minus 1 / 3) plus (1 / 3 minus 1 / 4) plus (1 / 4 minus 1 / 5). (1 / 2010 minus 1 / 2011) process It's a concrete process
• 15. For the first time, cut off 1 / 2 of the 2010 meter iron wire, cut off the remaining 1 / 3 in the second time, and so on, until the remaining 1 / 2010 is cut off, and calculate the length of the remaining iron wire
• 16. There are 2011 liters of kerosene. The first time we used it, the second time we used the rest, the third time we used the rest, and so on, until 2010 we used the rest There are 2011 liters of kerosene. The first time we used it, the second time we used the remaining 1 / 2, the third time we used the remaining 1 / 3, and so on. Until 2010, we used the remaining 1 / 2, and the remaining 1 / 3
• 17. There are 2011 liters of kerosene. For the first time, he used 1 / 2 of his kerosene, for the second time, he used the remaining 1 / 3, for the third time, he used the remaining 1 / 4, and so on. Until 2010, he used the remaining 1 / 2011, how many liters are left?
• 18. 1991 minus half of it, then minus the remaining 1 / 3, then minus the remaining 1 / 4... And so on, finally minus the remaining 1 / 1991
• 19. 2005 minus his half, and then minus the remaining half, until the 2005 one, ask the remaining number
• 20. 2011 minus 1 / 2, then minus the remaining 1 / 3, then minus the remaining 1 / 4, and so on, until finally minus the remaining 1 / 2011, find the last remaining number