Given the function f (x) = x2-2x, the area of the region formed by the point (x, y) satisfying the condition f (x) + F (y) ≤ 0f (x) − f (y) ≥ 0 is () A. 4πB. 2πC. 3π2D. π

∵ f (x) = x2-2x ∵ the constraint condition f (x) + F (y) ≤ 0f (x) − f (y) ≥ 0 can be transformed into (x − 1) 2 + (Y − 1) 2 ≤ 2 (x − 1) 2 − (Y − 1) 2 ≥ 0, and its corresponding feasible region is shown as follows: its area is: 12 ·π· (2) 2 = π, so D is selected

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