A cylindrical steel part with a bottom radius of 10 cm and a height of 15 cm is melted and cast into a conical steel part with a height of 60 cm. The bottom area of the cone should be

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Let the base area of the cone be x square centimeter (^ 2 for square)
60X×1/3＝3.14×10^2×15
20X＝4710
X＝4710÷20
X＝235.5
Formula solution:
The volume of the cylinder is:
3.14 × 10 ^ 2 × 15 = 4710 (cm3)
Cone bottom area:
4710 ／ 1 / 3 ／ 60 = 235.5 (cm2)

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