Given that the first-order function f (x) = (M2-1) x + m2-3m + 2 is a decreasing function on R, and f (1) = 3, the value of M is obtained

∵ a function f (x) is a decreasing function on R, ∵ M2-1 < 0, the solution is - 1 < m < 1, and f (1) = 3, ∵ M2-1 + m2-3m + 2 = 3, that is, 2m2-3m-2 = 0, the solution is m = 2 (rounding) or M = - 12, so the value of M is - 12

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