If the minimum value of function f (x) = 4x ^ 2-4ax + A ^ 2-2a + 2 in the interval [0,2] is 3, find the value of A I can't ask. Please explain exactly step by step and pray for the answer!

The quadratic function opens up and reaches the vertex when x = A / 2
When a / 2

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1. Given that the minimum value of F (x) = x2 + 2 (A-1) x + 2 in the interval [1,5] is f (5), then the value range of a is______ ．
2. Given that the minimum value of F (x) = x2 + 2 (A-1) x + 2 in the interval [1,5] is f (5), then the value range of a is______ ．
3. We know the function y = (2-m) x + 2m-3. When m is the value of (1) this function is a linear function? (2) Is this function a positive scale function?
4. Given the function y = (2m-3) x + m + 2. (1) if the function image passes through the origin, find the value of M. (2) if the function image passes through the point (- 1,0), find the value of M. (3) The function y = (2m-3) x + m + 2 is known. (1) if the function image passes through the origin, find the value of M. (2) if the function image passes through the point (- 1,0), find the value of M. (3) if the function image is parallel to the straight line y = - x + 2, find the value of M. (4) if the function image passes through the first, second and fourth quadrants, find the value range of M
5. Given the function y = (2m-1) x + m + 3, ask the function to pass through the origin and find the value of M
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