Given that the images of the function y = (A-2) x ^ 2 + 2 (A-4) x-4 are all above the x-axis, can you give me a detailed answer

When a = 2, y = - 4Y, does not meet the problem. When a is not equal to 2, according to the condition: A-2 > 0 (meaning the opening of quadratic function upward) △ = 4 (A-4) ^ 2 + 16 (A-2) = > A ^ 2-4a + 8

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