Given x + 2Y = 1, find the minimum value of 2 / x + 1 / y
2/x+1/y
=(√2)²/x+(√2)²/(2y)
≥(√2+√2)²/(x+2y)
=8,
∴(2/x+1/y)|min=8.
In this case, x = 1 / 2, y = 1 / 4
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